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2x^2/3-7=91
We move all terms to the left:
2x^2/3-7-(91)=0
We add all the numbers together, and all the variables
2x^2/3-98=0
We multiply all the terms by the denominator
2x^2-98*3=0
We add all the numbers together, and all the variables
2x^2-294=0
a = 2; b = 0; c = -294;
Δ = b2-4ac
Δ = 02-4·2·(-294)
Δ = 2352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2352}=\sqrt{784*3}=\sqrt{784}*\sqrt{3}=28\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{3}}{2*2}=\frac{0-28\sqrt{3}}{4} =-\frac{28\sqrt{3}}{4} =-7\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{3}}{2*2}=\frac{0+28\sqrt{3}}{4} =\frac{28\sqrt{3}}{4} =7\sqrt{3} $
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